Sunday 3 April 2016

Quantitative Aptitude Quiz - 32 | Bank exams


Directions(1-5): What value should come in place of question mark (?) in the following questions.

1. 1/2 of 5/7 of 14/15 of ? = 415
a) 1315
b) 1125
c) 1450
d) 1245
e) 1255
2. 1312/41 x 15 = 892 - ?
a) 468
b) 512
c) 412
d) 450
e) 434

3. 407.4 + 562.6 - 592 = 734.1 - ?
a) 256.1
b) 339.2
c) 452.6
d) 402.6
e) 356.1

4. 150% of 950/25 - 43 = ?% of 1400/25
a) 25
b) 55
c) 15
d) 20
e) 35

5. 154 + 36/6 x 221/17 = ?
a) 256
b) 202
c) 274
d) 280
e) 232

6.The sum of two numbers is 583. If the second number is 3/8 th of the first number, what is the difference between 1/4 th of the first number and 1/3 rd of the second number?
a) 58
b) 41
c) 53
d) 49
e) 62

7.At present, Ajay's age is twice that of Rohan. 8 years ago, Ajay's age was 4 times Rohan's age at that time. What will be Rohan's age after 6 years?
a) 32
b) 30
c) 18
d) 20
e) 24

8.A and B started a business by investing Rs 22,400 and Rs 18,200 respectively. After 4 months, C joined them by investing Rs 12,600. If the annual profit earned by them is Rs 12,670. What is C's share of profit?
a) Rs 2232
b) Rs 2364
c) Rs 2148
d) Rs 2244
e) Rs 2172

9.The speed of a car increases by 4 kmph every hour. If the distance traveled in the first one hour was 32 km, what was the total distance traveled by the car in 11 hours?
a) 596
b) 584
c) 564
d) 612
e) 572

10.The S.I obtained after certain years at 24% pa on a certain sum of money is twice the S.I that could have been obtained had the same sum of money been invested for 2 years more than the original period at a rate of 10% pa. What is the original period for which the sum was invested?
a) 20
b) 8
c) 10
d) 14
e) 12

Answers

(1-5)
1.(4)
2.(3)
3.(5)
4.(1)
5.(5)

6.(3)
Let the numbers be x and y.
y = 3x/8
x + y = 583
x + 3x/8 = 583
11x/8 = 583
x = 53 x 8
x/4 = 106
y/3 = 53
x/4 - y/3 = 106 - 53 = 53

7.(3)
Let Rohan's age be x
Then Ajay's age = 2x
8 year ago,
(2x - 8)=4(x - 8)
2x - 8 = 4x - 32
2x = 24
x = 12
After 6 years, Rohan's age will be 12 + 6 = 18.

8.(5)
Ratio of profits
A : B : C = 22400 X 12 : 18200 X 12 : 12600 X 8
A : B : C = 16 : 13 : 6
C's share = 6/35 x 12670 = 2172

9.(5)
Total disatnce covered = 32 + 36 + 40 + 44 + 48 + 52 + 56 + 60 + 64 + 68 + 72 = 572

10.(3)
Let the sum be P and the time be T.
(P x T x 24)/100 = 2(P x (T + 2) x 10)/100
24T = 20T + 40
4T = 40
T = 10 years.



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