Quantitative Aptitude Quiz - 39 | Bank Exams

1.Anurag's annual income is Rs. 6,36,000/-. He spends 22% of his monthly income on paying bills, 18% on household items, 12% on paying his children's fees and 4% he donates to charity. If two-fifth of the remaining amount he invests in mutual funds. What is the amount left with him every month?

a)Rs 17,850/-

b)Rs 12,162/-

c)Rs 9,328/-

d)Rs 13,992/-

e)Rs 14, 650/-

2.The population of a state in the year 2013 was 1,12,929. If the rate of increase was 10% and 20% respectively from the year 2011 to 2012 and 2012 to 2013, what was the population in the year 2011?

a)85,550

b)86,450

c)79,550

d)75,550

e)76,950

Directions(3 - 5): Study the information carefully to answer the following questions.

There are 4 red balls, 4 green balls and 6 blue balls in a box.

3.If two balls are drawn at random, what is the probability that at least one of them is blue?

a)6/13

b)7/13

c)8/13

d)10/13

e)9/13

4.If one ball is drawn at random, what is the probability that it is either red or blue?

a)5/9

b)7/9

c)4/7

d)3/7

e)5/7

5.If three balls are drawn at random, what is the probability that one of them is green and the other two are blue?

a)15/91

b)24/91

c)20/91

d)10/91

e)12/91

Directions(6 - 10): In the given questions, two equations numbered I and II are given. You have to solve both the equations and

Give answer:

a) x < y

b) x > y

c) x > = y

d) x < = y

e)relationship between x and y cannot be established.

6.I. 2x^2 - 7x + 3 = 0

  II. 2y^2 - 7y + 6 = 0

7.I. 4x^2 + 16x + 15 = 0

  II. 2y^2 + 3y + 1 = 0

8.I. 9x^2 - 45x + 56 = 0

  II. 4y^2 - 17y + 18 = 0

9.I. 2x^2 + 11x + 14 = 0

  II. 2y^2 - 15y + 28 = 0

10.I. 6x^2 + 11x + 4 = 0

    II. 4y^2 - 7y - 2 = 0

Answers

1.(d)
Aurag's monthly income = 636000/12 = Rs 53,000
Investment in mutual fund = (53,000 x 44)/100 = Rs 23,320
Remaining amount = 23320 x 3/5 =Rs 13,992/-.

2.(a)
Let the population of the state in the year 2011 be x
According to the question,
x x 110/100 x 120/100 = 112926
x = 85550

3.(e)
Probability of no ball is blue = 8C2/14C2
Probability that at least one of them is blue = 1 - 8C2/14C2 = 1 - 4/13 = 9/13

4.(e)
Probability for either red or blue = 4C1/14C1 + 6C1/14C1 = 10/14 = 5/7

5.(a)
Probability for one green and other two blue = (4C1 X 6C2)/(14C3) = 15/91

6.(e)
x = 0.5, 3
y = 2, 1.5

7.(a)
x = -1.5, -2.5
y = - 0.5 , -1

8.(b)
x = 7/3 , 8/3
y = 2, 9/4

9.(a)
x = -2 , -7/2
y =  4 ,  7/2

10.(a)
x = -1/2, -4/3
y = 2, -1/4