1. Shobha's Mathematics test had 75 problems i.e 10 arithmetic, 30 algebra and 35 geometry problems. Although she answered 70% of the arithmetic, 40% of the algebra and 60% of the geometry problems correctly, she did not pass the test because she got less than 60% of the problems right. How many more questions she would have needed to earn a 60% passing grade?
- 1
- 3
- 5
- 4
- 6
2. If 50% of (x - y) = 30% of (x + y), then what percent of x is y?
- 23
- 21
- 24
- 27
- 25
3. Alfred started a business investing Rs 45,000. After 3 months, Peter joined him with a capital of Rs. 60,000. After another 6 months, Ronald joined them with a capital of Rs. 90,000. At the end of the year, they made a profit of Rs 16,500. Find Peter's share.
- 6600
- 3300
- 1100
- 2200
- 6000
4. A, B and C enter into a partnership. A invests 3 times as much as B invest and B invest two - third of what C invests. At the end of the year, the profit earned is Rs 6600. Find B's share.
- 1100
- 1000
- 1400
- 1200
- 1110
5.Adam borrowed some money at the rate of 6% p.a for the first two years, at the rate of 9% p.a. for the next three years, and at the rate of 14% p.a for the period beyond five years. If he pays a total interest of Rs 11,400 at the end of nine years, how much money did he borrow?
- 12,000
- 22,000
- 10,000
- 13,000
- 14,000
Directions(6 - 10): Find the missing number in each series
6. 16 33 65 131 261 ?
- 523
- 521
- 613
- 721
7. 7 26 63 124 215 342 ?
- 481
- 511
- 391
- 421
8. 165 195 255 285 345 ?
- 375
- 420
- 435
- 390
9. 71 76 69 74 67 72 ?
- 77
- 65
- 80
- 76
10. 9 12 11 14 13 ? 15
- 12
- 16
- 10
- 17
Answers
1.(3)
Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35) = 7 + 12 + 21 = 40.
Questions to be answered correctly for 60% grade = 60% of 75 = 45
Required number of Questions = 45 - 40 = 5.
2.(5)
50% of ( x - y) = 30% of ( x + y)
5 ( x - y) = 3 ( x + y)
2x = 8y
x = 4y
Required percentage = (y/x x 100)% = 25%
3.(1)
Ratio of their capitals = (45000 x 12) : (60000 x 9) : (90000 x 3)
= 540000 : 540000 : 270000
= 2 : 2 : 1
Peter's share = 16500 x 2/5 = 6600
4.(4)
Let C's capital be x. Then B's capital = Rs 2x/3
A's capital = Rs( 3 x 2x/3) = Rs 2x
Ratio of their capital's = 2x : 2x/3 : x = 6 : 2 : 3.
Hence B's share = Rs(6600 x 2/11) = Rs 1200
5.(1)
Let the sum borrowed be y. Then,
(y x 6 x 2)/100 + (y x 9 x 3)/100 + (y x 14 x 4)/100 = 11400
solving the above equation, we get y = 12,000
6.(1)
Each number is twice the preceding one with 1 added or subtracted alternately.
So, the next number is ( 2 x 261 + 1) = 523.
7.(2)
Numbers are (2^3 - 1), (3^3 - 1), (4^4 - 1) and so on
So, next number is (8^3 - 1) = 511.
8.(3)
Each number is 15 multiplied by a prime number i.e, 15 x 11, 15 x 13, 15 x 17, 15 x 19, 15 x 23.
So, the next number is 15 x 29 = 435
9.(2)
Alternately, we add 5 and subtract 7.
10.(2)
Alternately, we add 3 and subtract 1.
1.(3)
Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35) = 7 + 12 + 21 = 40.
Questions to be answered correctly for 60% grade = 60% of 75 = 45
Required number of Questions = 45 - 40 = 5.
2.(5)
50% of ( x - y) = 30% of ( x + y)
5 ( x - y) = 3 ( x + y)
2x = 8y
x = 4y
Required percentage = (y/x x 100)% = 25%
3.(1)
Ratio of their capitals = (45000 x 12) : (60000 x 9) : (90000 x 3)
= 540000 : 540000 : 270000
= 2 : 2 : 1
Peter's share = 16500 x 2/5 = 6600
4.(4)
Let C's capital be x. Then B's capital = Rs 2x/3
A's capital = Rs( 3 x 2x/3) = Rs 2x
Ratio of their capital's = 2x : 2x/3 : x = 6 : 2 : 3.
Hence B's share = Rs(6600 x 2/11) = Rs 1200
5.(1)
Let the sum borrowed be y. Then,
(y x 6 x 2)/100 + (y x 9 x 3)/100 + (y x 14 x 4)/100 = 11400
solving the above equation, we get y = 12,000
6.(1)
Each number is twice the preceding one with 1 added or subtracted alternately.
So, the next number is ( 2 x 261 + 1) = 523.
7.(2)
Numbers are (2^3 - 1), (3^3 - 1), (4^4 - 1) and so on
So, next number is (8^3 - 1) = 511.
8.(3)
Each number is 15 multiplied by a prime number i.e, 15 x 11, 15 x 13, 15 x 17, 15 x 19, 15 x 23.
So, the next number is 15 x 29 = 435
9.(2)
Alternately, we add 5 and subtract 7.
10.(2)
Alternately, we add 3 and subtract 1.
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